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MHT CET · Maths · Vector Algebra

The vector equation of the plane r=2i^+k^+λi^+μi^+2j^-3k^ in scalar product from is r.3i^+2k^=α , then α=

  1. A 2
  2. B 3
  3. C 1
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

Given, equation of plane
r=2i^+k^+λi^+μi^+2j^-3k^ (i)
Here , plane (i) passing through a (let) =2i^+k^ and parallel to vector b (let) =i^ and c=i^+2j^-3k^
We know that equation of plane passing through a point a and parallel to non-parallel vectors b and c is r.b×c=a.b×c=a b c
Now, a b c=20110012-3
=20-0+12-0=2
and b×c=i^j^k^10012-3=3i^+2k^
r3i^+2k^=2
Therefore , α=2