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MHT CET · Maths · Definite Integration

The value of the integral \(\int_1^2 \frac{x \mathrm{~d} x}{(x+2)(x+3)}\) is

  1. A \(\log \left(\frac{125}{16}\right)\)
  2. B \(\log \left(\frac{1024}{1125}\right)\)
  3. C \(\log \left(\frac{16}{125}\right)\)
  4. D \(\log \left(\frac{1125}{1024}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\log \left(\frac{1125}{1024}\right)\)

Step-by-step Solution

Detailed explanation

\(\frac{x}{(x+2)(x+3)} = \frac{3}{x+3} - \frac{2}{x+2}\) \(\int_1^2 \left(\frac{3}{x+3} - \frac{2}{x+2}\right) \mathrm{d} x = \left[\ln\left(\frac{(x+3)^3}{(x+2)^2}\right)\right]_1^2\)