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MHT CET · Maths · Inverse Trigonometric Functions

The value of \(\cot \left(\sum_{n=1}^{23} \cot ^{-1}\left(1+\sum_{k=1}^n 2 k\right)\right)\) is

  1. A \(\frac{23}{25}\)
  2. B \(\frac{25}{23}\)
  3. C \(\frac{23}{24}\)
  4. D \(\frac{24}{23}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{25}{23}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \cot \left(\sum_{n=1}^{23} \cot ^{-1}\left(1+\sum_{k=1}^n 2 k\right)\right) \\ & =\cot \left(\sum_{n=1}^{23} \cot ^{-1}\left(1+2 \times \frac{n(n+1)}{2}\right)\right) \\ & =\cot \left(\sum_{n=1}^{23} \cot ^{-1}(1+n(n+1))\right)\end{aligned}\)
\(\begin{aligned} & =\cot \left(\sum_{n=1}^{23} \tan ^{-1}\left(\frac{1}{1+\mathrm{n}(\mathrm{n}+1)}\right)\right) \\ & =\cot \left(\sum_{\mathrm{n}=1}^{23} \tan ^{-1}\left(\frac{\mathrm{n}+1-\mathrm{n}}{1+\mathrm{n}(\mathrm{n}+1)}\right)\right) \\ & =\cot \left(\sum_{\mathrm{n}=1}^{23} \tan ^{-1}(\mathrm{n}+1)-\sum_{\mathrm{n}-1}^{23} \tan ^{-1} \mathrm{n}\right) \\ & =\cot \left[\left(\tan ^{-1}(2)+\tan ^{-1}(3)+\ldots+\tan ^{-1}(24)\right)\right. \\ & =\cot \left(\tan ^{-1}(24)-\tan ^{-1}(1)\right) \\ & =\cot \left(\tan ^{-1}\left(\frac{24-1}{1+24(1)}\right)\right) \\ & =\cot \left(\tan ^{-1}\left(\frac{23}{25}\right)\right) \\ & =\cot \left(\cot ^{-1}\left(\frac{25}{23}\right)\right) \\ & =\frac{25}{23}\end{aligned}\)