MHT CET · Maths · Three Dimensional Geometry
The value of \(m\), such that \(\frac{x-4}{1}=\frac{y-2}{1}=\frac{2 z-m}{3}\) lies in the plane \(2 x-5 y+2 z=7\), is
- A 8
- B 10
- C 9
- D 7
Answer & Solution
Correct Answer
(C) 9
Step-by-step Solution
Detailed explanation
According to the given condition, point \(\left(4,2, \frac{\mathrm{~m}}{2}\right)\) lies on the plane \(2 x-5 y+2 z=7\).
\(\begin{aligned}
& \Rightarrow 2(4)-5(2)+2\left(\frac{\mathrm{~m}}{2}\right)=7 \\
& \Rightarrow \mathrm{~m}=9
\end{aligned}\)
\(\begin{aligned}
& \Rightarrow 2(4)-5(2)+2\left(\frac{\mathrm{~m}}{2}\right)=7 \\
& \Rightarrow \mathrm{~m}=9
\end{aligned}\)
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