MHT CET · Maths · Three Dimensional Geometry
The value of m such that \(\frac{x-4}{1}=\frac{y-2}{1}=\frac{z+\mathrm{m}}{2}\) lies in the plane \(2 x-4 y+z=7\) is
- A 7
- B -7
- C no real value
- D 4
Answer & Solution
Correct Answer
(B) -7
Step-by-step Solution
Detailed explanation
Point \((4,2,-\mathrm{m})\) should lie in the plane \(2 x-4 y+z=7\)
\(\begin{array}{ll}
\therefore \quad & 2(4)-4(2)-m=7 \\
& \Rightarrow m=-7
\end{array}\)
\(\begin{array}{ll}
\therefore \quad & 2(4)-4(2)-m=7 \\
& \Rightarrow m=-7
\end{array}\)
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