MHT CET · Maths · Three Dimensional Geometry
The value of \(\mathrm{k}\) such that \(\frac{x-4}{1}=\frac{y-2}{1}=\frac{z-k}{2}\) lies in the plane \(2 x-4 y+z=7\), is
- A No real value
- B 4
- C 7
- D -7
Answer & Solution
Correct Answer
(C) 7
Step-by-step Solution
Detailed explanation
\(\because 2 \times 1-4 \times 1+1 \times 2=0\) i.e. line is parallel to the plane now \(2 \times 4-4 \times 2+K=7\) (for having a common point) \(\Rightarrow K=7\)
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