MHT CET · Maths · Complex Number
The value of \(\frac{(\cos \theta+i \sin \theta)^4}{(\sin \theta+i \cos \theta)^5}=\) where \(i=\sqrt{-1}\)
- A \(\cos \theta-i \sin \theta\)
- B \(\cos 9 \theta-\mathrm{i} \sin 9 \theta\)
- C \(\sin \theta-i \cos \theta\)
- D \(\sin 9 \theta-i \cos 9 \theta\)
Answer & Solution
Correct Answer
(D) \(\sin 9 \theta-i \cos 9 \theta\)
Step-by-step Solution
Detailed explanation
\( (\cos \theta+i \sin \theta)^4 = \cos 4\theta + i \sin 4\theta \) \( (\sin \theta+i \cos \theta)^5 = (i(\cos \theta - i \sin \theta))^5 = i^5 (\cos(-\theta) + i \sin(-\theta))^5 \)
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