MHT CET · Maths · Inverse Trigonometric Functions
The value of \(\operatorname{cosec}^{-1}(\sqrt{2})+\cos ^{-1}\left(\frac{-1}{2}\right)-\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right)\) is equal to
- A \(\frac{3 \pi}{4}\)
- B \(\frac{\pi}{6}\)
- C \(\frac{2 \pi}{3}\)
- D \(\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{3 \pi}{4}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \operatorname{cosec}^{-1}(\sqrt{2})+\cos ^{-1}\left(\frac{-1}{2}\right)-\sec ^{-1}\left(\frac{2}{\sqrt{3}}\right) \\ & =\frac{\pi}{4}+\frac{2 \pi}{3}-\frac{\pi}{6}=\frac{3 \pi}{4}\end{aligned}\)
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