MHT CET · Maths · Quadratic Equation
The value of ' \(a\) ' so that the sum of squares of the roots of the equation \(x^2-(a-2) x-a+1=0\) assumes the least value is
- A \(2\)
- B \(1\)
- C \(4\)
- D \(0\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(\alpha+\beta = a-2\) \(\alpha\beta = -(a-1)\)
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