ExamBro
ExamBro
MHT CET · Maths · Indefinite Integration

The value of \(\int \frac{\cos ^3 x}{\sin ^2 x+\sin x} \mathrm{~d} x\) is

  1. A \(\quad \log (\sin x)-\sin x+\mathrm{c}\), where c is a constant of integration.
  2. B \(\log (\sin x)-\cos x+\mathrm{c}\), where c is a constant of integration.
  3. C \(\log (\sin x)+\sin x+\mathrm{c}\), where c is a constant of integration.
  4. D \(\log (\cos x)-\cos x+\mathrm{c}\), where c is a constant of integration.
Verified Solution

Answer & Solution

Correct Answer

(A) \(\quad \log (\sin x)-\sin x+\mathrm{c}\), where c is a constant of integration.

Step-by-step Solution

Detailed explanation

\(\begin{aligned}
& I=\int \frac{\left(1-\sin ^2 x\right) \cos x}{\sin x(1+\sin x)} d x \\
& =\int \frac{1-\sin x}{\sin x} \cos x d x
\end{aligned}\)

Put \(t=\sin x\)
\(\Rightarrow \cos x d x=d t\)

So, \(I=\int\left(\frac{1}{t}-1\right) d t\)
\(\begin{aligned}
& =\log t-t+C \\
& \Rightarrow I=\log \sin x-\sin x+C
\end{aligned}\)