MHT CET · Maths · Trigonometric Ratios & Identities
The value of \(\tan \frac{\pi}{3}+2 \tan \frac{2 \pi}{3}+4 \tan \frac{4 \pi}{3}+8 \tan \frac{8 \pi}{3}\) is equal to
- A \(-5 \sqrt{3}\)
- B \(5 \sqrt{3}\)
- C \(-10 \sqrt{3}\)
- D \(15 \sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(-5 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\( \tan \frac{\pi}{3} = \sqrt{3} \) \( \tan \frac{2 \pi}{3} = -\sqrt{3} \)
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