MHT CET · Maths · Inverse Trigonometric Functions
The value of \(\cos ^{-1}\left(\cos \frac{8 \pi}{3}\right)\) is
- A \(\frac{8 \pi}{3}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{2 \pi}{3}\)
- D \(\frac{3 \pi}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{2 \pi}{3}\)
Step-by-step Solution
Detailed explanation
\(\cos \frac{8 \pi}{3} = \cos \left(2\pi + \frac{2\pi}{3}\right) = \cos \frac{2\pi}{3}\) \(\cos ^{-1}\left(\cos \frac{8 \pi}{3}\right) = \cos ^{-1}\left(\cos \frac{2\pi}{3}\right) = \frac{2\pi}{3}\)
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