MHT CET · Maths · Inverse Trigonometric Functions
The value of \(\cos ^{-1}\left(\cos \left(\frac{7 \pi}{6}\right)\right)\) is
- A \(\frac{5 \pi}{6}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{7 \pi}{6}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(A) \(\frac{5 \pi}{6}\)
Step-by-step Solution
Detailed explanation
Let \(\alpha\) and \(\beta\) are roots of quadratic equation Given, \(\frac{\alpha+\beta}{2}=34\) \(\alpha+\beta=68\)
and \(\sqrt{\alpha \beta}=16\) \(\alpha \beta=256\)
\(\therefore\) Required quadratic equation is, \(x^{2}-(\alpha+\beta) x+\alpha \beta=0\) \(x^{2}-68 x+256=0\)
and \(\sqrt{\alpha \beta}=16\) \(\alpha \beta=256\)
\(\therefore\) Required quadratic equation is, \(x^{2}-(\alpha+\beta) x+\alpha \beta=0\) \(x^{2}-68 x+256=0\)
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