MHT CET · Maths · Inverse Trigonometric Functions
The value of \(\tan ^{-1} 2+\tan ^{-1} 3\) is
- A \(\left(\frac{3 \pi}{4}\right)^c\)
- B \(\left(\frac{\pi}{2}\right)^c\)
- C \(\left(\frac{\pi}{4}\right)^c\)
- D \(\left(\frac{\pi}{6}\right)^c\)
Answer & Solution
Correct Answer
(A) \(\left(\frac{3 \pi}{4}\right)^c\)
Step-by-step Solution
Detailed explanation
\(\tan ^{-1} 2+\tan ^{-1} 3 \)
\( =\tan ^{-1}\left[\frac{2+3}{1-(2)(3)}\right]=\tan ^{-1}\left(\frac{5}{1-6}\right)=\tan ^{-1}\) \((-1)=\left(\frac{3 \pi}{4}\right)^c\)
\( =\tan ^{-1}\left[\frac{2+3}{1-(2)(3)}\right]=\tan ^{-1}\left(\frac{5}{1-6}\right)=\tan ^{-1}\) \((-1)=\left(\frac{3 \pi}{4}\right)^c\)
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