MHT CET · Maths · Inverse Trigonometric Functions
The value of \(\cos \left(\tan ^{-1}\left(\sin \left(\cot ^{-1} x\right)\right)\right)\) is
- A \(\sqrt{\frac{x^2+1}{x^2-1}}\)
- B \(\sqrt{\frac{1-x^2}{2+x^2}}\)
- C \(\sqrt{\frac{1-x^2}{1+x^2}}\)
- D \(\sqrt{\frac{x^2+1}{x^2+2}}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{\frac{x^2+1}{x^2+2}}\)
Step-by-step Solution
Detailed explanation
\(\cos \left(\tan ^{-1}\left(\sin \left(\cot ^{-1} x\right)\right)\right)=\) \(\cos \left(\tan ^{-1}\left(\sin \left(\sin ^{-1} \frac{1}{\sqrt{1+x^2}}\right)\right)\right) \)
\( =\cos \left(\tan ^{-1} \frac{1}{\sqrt{1+x^2}}\right)=\operatorname{coscos}^{-1} \frac{\sqrt{1+x^2}}{\sqrt{2+x^2}}=\frac{\sqrt{x^2+1}}{\sqrt{x^2+2}}\)
\( =\cos \left(\tan ^{-1} \frac{1}{\sqrt{1+x^2}}\right)=\operatorname{coscos}^{-1} \frac{\sqrt{1+x^2}}{\sqrt{2+x^2}}=\frac{\sqrt{x^2+1}}{\sqrt{x^2+2}}\)
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