The value of \(\int_{0}^{\pi / 2} \frac{\cos 3 x+1}{2 \cos x-1} d x\) is

Let \(I=\int_{0}^{\pi / 2} \frac{\cos 3 x+1}{2 \cos x-1} d x \)
\( =\int_{0}^{\pi / 2} \frac{\cos 3 x-\cos \frac{3 \pi}{3}}{2\left(\cos x-\cos \frac{\pi}{3}\right)} d x \)
\(=\int_{0}^{\pi / 2} \frac{\left(4 \cos ^{3} x-3 \cos x\right)-\left(4 \cos ^{3} \frac{\pi}{3}-3 \cos \frac{\pi}{3}\right)}{2\left(\cos x-\cos \frac{\pi}{3}\right)} d x \)
\(= 2 \int_{0}^{\pi / 2}\left(\frac{\cos ^{3} x-\cos ^{3} \frac{\pi}{3}}{\cos x-\cos \frac{\pi}{3}}\right) d x \)
\(=\frac{3}{2} \int_{0}^{\pi / 2}\left(\frac{\cos x-\cos \frac{\pi}{3}}{\cos x-\cos \frac{\pi}{3}}\right) d x \)
\(= \int_{0}^{\pi / 2}\left(1+\cos 2 x+\frac{1}{2}+\cos x\right) d x-\frac{3 \pi}{4} \)
\(= \frac{3 \pi}{4}+1-\frac{3 \pi}{4}=1\)