The teacher wants to arrange 5 students on the platform such that the boy \(\mathrm{B}_1\) occupies second position and the girls \(\mathrm{G}_1\) and \(\mathrm{G}_2\) are always adjacent to each other, then the number of such arrangements is

There are 5 positions. Given that \(\mathrm{B}_1\) occupies \(2^{\text {nd}}\) position
\(\therefore \mathrm{B}_1\) can be arranged in 1 way. As \(G_1\) and \(G_2\) are always together, none of them can take \(1^{\text {st}}\) position.
\(\therefore \mathrm{G}_1, \mathrm{G}_2\) and one of the remaining students can be arranged on \(3^{\text {rd}}, 4^{\text {th}}\) and \(5^{\text {th}}\) position when \(\mathrm{G}_1\) and \(\mathrm{G}_2\) are always together in \(2 ! \times 2!\) Ways.
And remaining 2 students can be arranged in \(2!\) Ways.
\(\therefore\) The required number of arrangements
\(=2 ! \times 2 ! \times 2 !\)
\(=8\)