MHT CET · Maths · Circle
The tangent to the circle \(x^2+y^2=5\) at \((1,-2)\) also touches the circle \(x^2+y^2-8 x+6 y+20=0\) then the co-ordinates of the corresponding point of contact is
- A \((3,-1)\)
- B \(\quad(3,1)\)
- C \((-3,-1)\)
- D \((-3,1)\)
Answer & Solution
Correct Answer
(A) \((3,-1)\)
Step-by-step Solution
Detailed explanation
Equation of the tangent at \((1,-2)\) to the circle \(x^2+y^2=5\) is \(x-2 y=5\)
Here, only point \((3,-1)\) lies on the tangent.
Here, only point \((3,-1)\) lies on the tangent.
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