MHT CET · Maths · Pair of Lines
The straight lines represented by the equation \(9 x^{2}-12 x y+4 y^{2}=0\) are
- A coincident
- B perpendicular
- C intersect at \(60^{\circ}\)
- D parallel
Answer & Solution
Correct Answer
(D) parallel
Step-by-step Solution
Detailed explanation
(C)
The given pair of lines are of the form \(a x^{2}+2 h x y+b y^{2}=0 \Rightarrow a=9,2 h=-12, \Rightarrow h=-6,\)\( b=4\) \(h^{2}-a b=(-6)^{2}-(9 \times 4)=36-36=0\)
Therefore the lines are coincident
The given pair of lines are of the form \(a x^{2}+2 h x y+b y^{2}=0 \Rightarrow a=9,2 h=-12, \Rightarrow h=-6,\)\( b=4\) \(h^{2}-a b=(-6)^{2}-(9 \times 4)=36-36=0\)
Therefore the lines are coincident
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