MHT CET · Maths · Differential Equations
The solution of the differential equation
\(x \frac{\mathrm{~d}^2 \mathrm{y}}{\mathrm{d} x^2}=1 \quad\) at \(\quad x=\mathrm{y}=1\) with \(\frac{\mathrm{dy}}{\mathrm{d} x}=0\) at \(x=1\), is
- A \(\mathrm{y}=x \log x+x+2\)
- B \(\mathrm{y}=x \log x-x+2\)
- C \(\mathrm{y}=x \log x+2\)
- D \(x \log x-x=\mathrm{y}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{y}=x \log x-x+2\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{d} x^2}=\frac{1}{x}\) \(\frac{\mathrm{dy}}{\mathrm{d} x}=\int \frac{1}{x} \mathrm{d} x = \log x + C_1\)
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