MHT CET · Maths · Differential Equations
The solution of the differential equation. \((1+x) \frac{\mathrm{dy}}{\mathrm{d} x}-x \mathrm{y}=1-x\) is
- A \(\mathrm{y}(1+x)=x+\mathrm{ce}^x\), where c is the constant of integration
- B \(\mathrm{y}(1+x)=\mathrm{ce}^x\), where c is the constant of integration
- C \(\mathrm{y}(1-x)=x-\mathrm{ce}^x\), where c is the constant of integration
- D \(\mathrm{y}(1+x)=x~ \mathrm{ce}^{-x}\), where c is the constant of integration
Answer & Solution
Correct Answer
(A) \(\mathrm{y}(1+x)=x+\mathrm{ce}^x\), where c is the constant of integration
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{dy}}{\mathrm{d} x} - \frac{x}{1+x} \mathrm{y} = \frac{1-x}{1+x}\) IF \( = e^{\int -\frac{x}{1+x} \mathrm{d} x} = e^{\int (-1 + \frac{1}{1+x}) \mathrm{d} x} = e^{-x + \ln|1+x|} = (1+x)e^{-x}\)
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