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MHT CET · Maths · Straight Lines

The slope of the line through the origin which makes an angle of \(30^{\circ}\) with the positive direction of \(\mathrm{Y}\)-axis measured anticlockwise is

  1. A \(\frac{-2}{\sqrt{3}}\)
  2. B \(-\sqrt{3}\)
  3. C \(\frac{\sqrt{3}}{2}\)
  4. D \(\frac{-1}{\sqrt{3}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-\sqrt{3}\)

Step-by-step Solution

Detailed explanation


Refer figure
Angle made by line \(\mathrm{L}\) with positive direction of \(\mathrm{X}\) axis is \(\left(90^{\circ}+30^{\circ}\right)\) i.e. \(120^{\circ}\).
\(\therefore\) Slope of line \(\mathrm{L}=\tan \left(120^{\circ}\right)=\tan \left(\pi-60^{\circ}\right)=-\tan 60^{\circ}=-\sqrt{3}\)
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