MHT CET · Maths · Straight Lines
The slope of the line through the origin which makes an angle of \(30^{\circ}\) with the positive direction of \(\mathrm{Y}\)-axis measured anticlockwise is
- A \(\frac{-2}{\sqrt{3}}\)
- B \(-\sqrt{3}\)
- C \(\frac{\sqrt{3}}{2}\)
- D \(\frac{-1}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(B) \(-\sqrt{3}\)
Step-by-step Solution
Detailed explanation

Refer figure
Angle made by line \(\mathrm{L}\) with positive direction of \(\mathrm{X}\) axis is \(\left(90^{\circ}+30^{\circ}\right)\) i.e. \(120^{\circ}\).
\(\therefore\) Slope of line \(\mathrm{L}=\tan \left(120^{\circ}\right)=\tan \left(\pi-60^{\circ}\right)=-\tan 60^{\circ}=-\sqrt{3}\)
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