MHT CET · Maths · Three Dimensional Geometry
The shortest distance between the lines
\(\begin{aligned} & \overline{\mathrm{r}}=(4 \hat{i}-\hat{j})+\lambda(\hat{i}+2 \hat{j}-3 \hat{k}) \text { and } \\ & \overline{\mathrm{r}}=(\hat{i}-\hat{j}+2 \hat{k})+\mu(2 \hat{i}+4 \hat{j}-5 \hat{k}) \text { is }\end{aligned}\)
- A \(\frac{1}{\sqrt{5}}\) units
- B \(\frac{6}{\sqrt{5}}\) units
- C \(\frac{2}{\sqrt{5}}\) units
- D \(\frac{3}{\sqrt{5}}\) units
Answer & Solution
Correct Answer
(B) \(\frac{6}{\sqrt{5}}\) units
Step-by-step Solution
Detailed explanation
\( \overline{a_1} = 4 \hat{i} - \hat{j}, \overline{b_1} = \hat{i} + 2 \hat{j} - 3 \hat{k} \) \( \overline{a_2} = \hat{i} - \hat{j} + 2 \hat{k}, \overline{b_2} = 2 \hat{i} + 4 \hat{j} - 5 \hat{k} \)
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