MHT CET · Maths · Linear Programming

The shaded figure given below is the solution set for the linear inequations. Choose the correct option

A \(3 x+4 y \geq 18 ; x-6 y \leq 3 ; 2 x+3 y \geq 3 ; 7 x-14 \leq 14;\) \( x \geq0 ; \mathrm{y} \geq 0\)
B \(3 x+4 y \leq 18 ; x-6 y \leq 3 ; 2 x+3 y \leq 3 ;-7 x+14 \geq\) \(14 ;\) \( x \geq0 ; \mathrm{y} \geq 0\)
C \(3 x+4 y \leq 18 ; x-6 y \leq 3 ; 2 x+3 y \geq 3 ;-7 x+14 \leq\) \(14 ;\) \( x \geq 0 ; y \geq 0\)
D \(3 \mathrm{x}+4 \mathrm{y} \geq-18 ; \mathrm{x}-6 \mathrm{y} \leq 3 ; 2 \mathrm{x}+3 \mathrm{y} \leq 3 ;-7 \mathrm{x}+14 \geq\) \(14 ;\) \(\mathrm{x} \geq 0 ; \mathrm{y} \geq 0\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(3 x+4 y \leq 18 ; x-6 y \leq 3 ; 2 x+3 y \geq 3 ;-7 x+14 \leq\) \(14 ;\) \( x \geq 0 ; y \geq 0\)

Step-by-step Solution

Detailed explanation

For the shaded region, inequalities are as follows, \(x \geq 0, y \geq 0,2 x+3 y \geq 3, x-6 y \leq 3,3 x+4 y \leq 18,-\) \(7 x+14 y \leq 14\) Note:
\(
-7 x+14 y=14 \Rightarrow 7 x-14=-14 \text { and } 0>-14
\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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