MHT CET · Maths · Application of Derivatives
The rate of change of the volume of a sphere with respect to its surface area, when the radius is 5 m is
- A \(\frac{5}{2} \mathrm{~m}\)
- B \(\frac{2}{5} \mathrm{~m}\)
- C \(\frac{1}{2} \mathrm{~m}\)
- D \(\frac{1}{3} \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(\frac{5}{2} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(V = \frac{4}{3}\pi r^3\), \(A = 4\pi r^2\) \(\frac{dV}{dr} = 4\pi r^2\)
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