MHT CET · Maths · Differential Equations
The rate at which a substance cools in moving air, is proportional to the difference between the temperature of the substance and that of air. The temperature of air is 290 K and the substance cools from 370 K to 330 K in 10 minutes. Then the time to cool the substance upto 295 K is
- A 40 min
- B 96 min
- C 50 min
- D 60 min
Answer & Solution
Correct Answer
(A) 40 min
Step-by-step Solution
Detailed explanation
\( \frac{T - T_a}{T_0 - T_a} = e^{-kt} \) \( \frac{330 - 290}{370 - 290} = e^{-k \cdot 10} \)
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