MHT CET · Maths · Probability
The probability that the person who undergoes certain operation will survive is \(0 \cdot 2 .\) If 5 patients undergo similar operations, then the probability that exactly four will survive is
- A \(0.0042\)
- B \(0.0084\)
- C \(0 \cdot 0032\)
- D \(0 \cdot 0064\)
Answer & Solution
Correct Answer
(D) \(0 \cdot 0064\)
Step-by-step Solution
Detailed explanation
Since there are 5 patients, n = 5
P(Pprobability of patient survive) = 0.2
\(p-0.2 \Rightarrow q=1-p=1-0.2=08\)
\(P(x=4)={ }^{5} C_{4}(0.2)^{4}(0.8)^{1}=5 \times 0.0016 ~\times\) \(0.8=0.0064\)
P(Pprobability of patient survive) = 0.2
\(p-0.2 \Rightarrow q=1-p=1-0.2=08\)
\(P(x=4)={ }^{5} C_{4}(0.2)^{4}(0.8)^{1}=5 \times 0.0016 ~\times\) \(0.8=0.0064\)
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