MHT CET · Maths · Probability
The probability that a non leap year selected at random will contain 52 Saturdays or 53 Sundays is
- A \(\frac{1}{7}\)
- B \(\frac{6}{7}\)
- C \(\frac{2}{7}\)
- D \(\frac{5}{7}\)
Answer & Solution
Correct Answer
(B) \(\frac{6}{7}\)
Step-by-step Solution
Detailed explanation
A non-leap year has \( 365 \) days = \( 52 \) weeks + \( 1 \) day. The extra day can be any of \( 7 \) days (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday), each with probability \( \frac{1}{7} \).
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