MHT CET · Maths · Probability
The probability that a certain kind of component will survive a given test is \(\frac{2}{3}\). The probability that at most 2 components out of 4 tested, will survive is
- A \(\frac{31}{3^4}\)
- B \(\frac{32}{3^4}\)
- C \(\frac{33}{3^4}\)
- D \(\frac{35}{3^4}\)
Answer & Solution
Correct Answer
(C) \(\frac{33}{3^4}\)
Step-by-step Solution
Detailed explanation
\( P(X \le 2) = P(X=0) + P(X=1) + P(X=2) \) \( P(X=k) = \binom{4}{k} (\frac{2}{3})^k (\frac{1}{3})^{4-k} \)
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