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MHT CET · Maths · Probability

The probability that a certain kind of component will survive a given test is \(\frac{2}{3}\). The probability that at most 2 components out of 4 tested, will survive is

  1. A \(\frac{31}{3^4}\)
  2. B \(\frac{32}{3^4}\)
  3. C \(\frac{33}{3^4}\)
  4. D \(\frac{35}{3^4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{33}{3^4}\)

Step-by-step Solution

Detailed explanation

\( P(X \le 2) = P(X=0) + P(X=1) + P(X=2) \) \( P(X=k) = \binom{4}{k} (\frac{2}{3})^k (\frac{1}{3})^{4-k} \)