MHT CET · Maths · Probability
The probability distribution of a discrete random variable X is
\(\begin{array}{||c|c|c|c|c|c|} \hline \mathrm{X} & 0 & 1 & 2 & 3 & 4 \\ \hline \mathrm{P}(\mathrm{X}=x) & 2 \mathrm{k} & \mathrm{k} & 2 \mathrm{k} & 4 \mathrm{k} & \mathrm{k} \\ \hline \end{array}\)
If \(\mathrm{a}=\mathrm{P}(x < 3)\) and \(\mathrm{b}=\mathrm{P}(2 < \mathrm{x} < 4)\), then
- A \(a=b\)
- B \(a>b\)
- C \(\mathrm{a} < \mathrm{b}\)
- D \(a=\frac{1}{2} b\)
Answer & Solution
Correct Answer
(B) \(a>b\)
Step-by-step Solution
Detailed explanation
\(\sum P(X=x) = 1 \implies 2k + k + 2k + 4k + k = 1 \implies 10k = 1 \implies k = \frac{1}{10}\) \(a = P(X < 3) = P(X=0) + P(X=1) + P(X=2)\)
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