MHT CET · Maths · Probability
The probability distribution of a discrete r. v. \(X\) is
then value of \(\mathrm{P}(\mathrm{X} \leq 2)\) is
- A \(\frac{1}{10}\)
- B \(\frac{7}{10}\)
- C \(\frac{3}{10}\)
- D \(\frac{9}{10}\)
Answer & Solution
Correct Answer
(B) \(\frac{7}{10}\)
Step-by-step Solution
Detailed explanation
Here \(\mathrm{k}+2 \mathrm{k}+4 \mathrm{k}+2 \mathrm{k}+\mathrm{k}=10 \mathrm{k}=1 \Rightarrow \mathrm{k}=\frac{1}{10}\)
Now \(\mathrm{P}(\mathrm{X} \leq 2)=\mathrm{P}(0)+\mathrm{P}(1)+\mathrm{P}(2)=\frac{1}{10}+\frac{2}{10}\) \(+~\frac{4}{10}=\frac{7}{10}\)
Now \(\mathrm{P}(\mathrm{X} \leq 2)=\mathrm{P}(0)+\mathrm{P}(1)+\mathrm{P}(2)=\frac{1}{10}+\frac{2}{10}\) \(+~\frac{4}{10}=\frac{7}{10}\)
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