MHT CET · Maths · Inverse Trigonometric Functions
The principal value of \(\sin ^{-1}\left(-\frac{1}{2}\right)\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{6}\)
- C \(-\frac{\pi}{3}\)
- D \(-\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(D) \(-\frac{\pi}{6}\)
Step-by-step Solution
Detailed explanation
\(\sin ^{-1}\left(-\frac{1}{2}\right)=-\sin ^{-1} \frac{1}{2}=\frac{-\pi}{6}\)
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