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MHT CET · Maths · Trigonometric Equations

The principal solutions of \(\cos 2 x=\frac{-1}{2}\) are

  1. A \(x=\frac{-2 \pi}{3}, x=\frac{4 \pi}{3}\)
  2. B \(x=\frac{\pi}{3}, \quad x=\frac{2 \pi}{3}\)
  3. C \(x=\frac{-\pi}{3}, \quad x=\frac{5 \pi}{6}\)
  4. D \(x=\frac{\pi}{3}, \quad x=\frac{7 \pi}{6}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x=\frac{\pi}{3}, \quad x=\frac{2 \pi}{3}\)

Step-by-step Solution

Detailed explanation

\(\cos 2 x=\frac{-1}{2} \)
\( \therefore \frac{-1}{2}=\cos \left(\pi-\frac{\pi}{3}\right)-\cos \left(\pi+\frac{\pi}{3}\right) \Rightarrow \frac{-1}{2}-\cos \frac{2 \pi}{3}-\)\(\cos \frac{4 \pi}{3} \)
\( \therefore 2 x=\frac{2 \pi}{3} \text { or } 2 x=\frac{4 \pi}{3} \Rightarrow x=\frac{\pi}{3} \text { or } \frac{2 \pi}{3}\)