MHT CET · Maths · Vector Algebra
The position vectors of vertices of a \(\Delta A B C\) are \(\begin{array}{lll}4 \hat{\mathbf{i}}-2 \hat{\mathbf{j}}, & \hat{\mathbf{i}}+4 \hat{\mathbf{j}}-3 \hat{\mathbf{k}} \quad \text { and } & -\hat{\mathbf{i}}+5 \hat{\mathbf{j}}+\hat{\mathbf{k}}\end{array}\)
respectively, then \(\angle A B C\) is equal to
- A \(\frac{\pi}{6}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{3}\)
- D \(\frac{\pi}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
Here \(, \overrightarrow{\mathbf{A B}}=-3 \hat{\mathbf{i}}+6 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}, \overrightarrow{\mathbf{B C}}=-2 \hat{\mathbf{i}}+\hat{\mathbf{j}}+4 \hat{\mathbf{k}}\)
and \(\overrightarrow{\mathbf{A B}} \cdot \overrightarrow{\mathbf{B C}}=6+6-12=0\)
\(\angle A B C=\frac{\pi}{2}\)
and \(\overrightarrow{\mathbf{A B}} \cdot \overrightarrow{\mathbf{B C}}=6+6-12=0\)
\(\angle A B C=\frac{\pi}{2}\)
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