MHT CET · Maths · Straight Lines
The point of intersection of the diagonals of the rectangle whose sides are contained in the lines \(x=8, x=10, \mathrm{y}=11\) and \(\mathrm{y}=12\) is
- A \(\left(\frac{9}{2}, 23\right)\)
- B \(\left(9, \frac{23}{2}\right)\)
- C \(\left(7, \frac{21}{2}\right)\)
- D \(\left(\frac{7}{2}, 21\right)\)
Answer & Solution
Correct Answer
(B) \(\left(9, \frac{23}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(x = \frac{8+10}{2} = 9\) \(y = \frac{11+12}{2} = \frac{23}{2}\)
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