MHT CET · Maths · Straight Lines
The perpendicular distance between the lines given by \((x-2 \mathrm{y}+1)^2+\mathrm{k}(x-2 \mathrm{y}+1)=0\) is \(\sqrt{5}\), then \(\mathrm{k}=\)
- A \(5\)
- B \(2\)
- C \(4\)
- D \(6\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\((x-2y+1)(x-2y+1+k)=0\) \(L_1: x-2y+1=0\)
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