MHT CET · Maths · Three Dimensional Geometry
The perimeter a square whose two sides have equations \(\frac{x-1}{2}=\frac{y+2}{3}=\frac{z-3}{4}\) and \(\frac{x}{2}=\frac{y-1}{3}=\frac{z+1}{4}\) is
- A \(\frac{\sqrt{673}}{\sqrt{29}}\) units
- B \(\frac{4 \sqrt{673}}{\sqrt{29}}\) units
- C \(\frac{4 \sqrt{573}}{\sqrt{29}}\) units
- D \(\frac{4}{\sqrt{29}}\) units
Answer & Solution
Correct Answer
(B) \(\frac{4 \sqrt{673}}{\sqrt{29}}\) units
Step-by-step Solution
Detailed explanation
Line 1 point \(P(1, -2, 3)\), Line 2 point \(Q(0, 1, -1)\), Direction vector \(\vec{v}=(2, 3, 4)\). Vector \(\vec{PQ} = Q - P = (0-1, 1-(-2), -1-3) = (-1, 3, -4)\).
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