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MHT CET · Maths · Differential Equations

The particular solution of the differential equation \(x d y+2 y d x=0\), when \(x=2\)
and \(y=1\) is

  1. A \(x y^{2}=4\)
  2. B \(x^{2} y=4\)
  3. C \(x^{2} y=-4\)
  4. D \(x y^{2}=-4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(x^{2} y=4\)

Step-by-step Solution

Detailed explanation

Given D.E. is \(x d y+2 y d x=0\)
\(\therefore x d y=-2 y d x \Rightarrow \int \frac{d y}{y}=\int-\frac{2 d x}{x}\)
\(\log y=-2 \log x+\log c \Rightarrow \log y+2 \log x=\log c\)
\(\therefore \quad \log y+\log x^{2}=\log c \Rightarrow x^{2} y=c\)
when \(x=2, y=1, c=4\)
\(\therefore\) Particular solution is \(\mathrm{x}^{2} \mathrm{y}=4\)
From MHT CET
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