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MHT CET · Maths · Differential Equations

The parametric equations of the curve \(x^2+y^2+a x+b y=0\) are

  1. A \(x=\frac{\mathrm{a}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=\frac{\mathrm{b}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta\)
  2. B \(x=\frac{\mathrm{a}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=\frac{\mathrm{b}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta\)
  3. C \(x=-\frac{\mathrm{a}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=-\frac{\mathrm{b}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta\)
  4. D \(x=-\frac{\mathrm{a}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=-\frac{\mathrm{b}}{2}-\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(x=-\frac{\mathrm{a}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=-\frac{\mathrm{b}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta\)

Step-by-step Solution

Detailed explanation

\(
\begin{aligned}
& x^2+y^2+\mathrm{a} x+\mathrm{b} y=0 \\
& \Rightarrow\left(x+\frac{\mathrm{a}}{2}\right)^2+\left(y+\frac{\mathrm{b}}{2}\right)^2=\frac{\mathrm{a}^2+\mathrm{b}^2}{4}
\end{aligned}
\)
Comparing with \((x-\mathrm{h})^2+(y-\mathrm{k})^2=\mathrm{r}^2\), we get
\(
\mathrm{h}=-\frac{\mathrm{a}}{2}, \mathrm{k}=-\frac{\mathrm{b}}{2}, \mathrm{r}=\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}}
\)
\(\therefore\) The parametric equations are
\(
x=-\frac{\mathrm{a}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \cos \theta, y=-\frac{\mathrm{b}}{2}+\sqrt{\frac{\mathrm{a}^2+\mathrm{b}^2}{4}} \sin \theta
\)