MHT CET · Maths · Permutation Combination
The number of ways in which a team of 11 players can be formed out of 25 players, if 6 out of them are always to be included and 5 of them are always to be excluded, is
- A 2002
- B \(^{20}C_{11}\)
- C \(^{20}C_{6}\)
- D \(^{14}C_{6}\)
Answer & Solution
Correct Answer
(A) 2002
Step-by-step Solution
Detailed explanation
\( \text{Players available for selection} = 25 - (6 + 5) = 14 \) \( \text{Players to be chosen} = 11 - 6 = 5 \)
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