MHT CET · Maths · Permutation Combination
The number of ways in which 8 different pearls can be arranged to from a necklace is
- A 40320
- B 5040
- C 2520
- D 1260
Answer & Solution
Correct Answer
(C) 2520
Step-by-step Solution
Detailed explanation
Number of necklaces formed from 8 different pearls
\(=\frac{(8-1) !}{2}=7 \times 6 \times 5 \times 4 \times 3=2520\)
\(=\frac{(8-1) !}{2}=7 \times 6 \times 5 \times 4 \times 3=2520\)
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