MHT CET · Maths · Permutation Combination
The number of ways in which 6 boys and 4 girls can be seated around a round table such that 2 special boys and a special girl never sit together is
- A 332620
- B 332540
- C 332640
- D 332520
Answer & Solution
Correct Answer
(C) 332640
Step-by-step Solution
Detailed explanation
Total arrangements = \( (10-1)! = 9! = 362880 \) Arrangements where 2 special boys and 1 special girl sit together = \( ( (10-3)+1 - 1 )! \times 3! = 7! \times 3! \)
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