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MHT CET · Maths · Vector Algebra

The number of unit vectors perpendicular to \(\overline{\mathrm{a}}=(1,1,0)\) and \(\overline{\mathrm{b}}=(0,1,1)\) is

  1. A one.
  2. B two.
  3. C three.
  4. D infinite.
Verified Solution

Answer & Solution

Correct Answer

(B) two.

Step-by-step Solution

Detailed explanation

The vector perpendicular to \(\overline{\mathrm{a}}\) and \(\overline{\mathrm{b}}\) is
\(\bar{a} \times \bar{b}=\left|\begin{array}{lll}
\hat{i} & \hat{j} & \hat{k} \\
1 & 1 & 0 \\
0 & 1 & 0
\end{array}\right|=\hat{i}-\hat{j}+\hat{k}\)
Since the length of this vector is \(\sqrt{3}\), the unit vector perpendicular to \(\overline{\mathrm{a}}\) and \(\overline{\mathrm{b}}\) is \(\pm \frac{\overline{\mathrm{a}} \times \overline{\mathrm{b}}}{|\overline{\mathrm{a}} \times \overline{\mathrm{b}}|}= \pm \frac{1}{\sqrt{3}}(\hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}})\)
Hence, there are two such vectors.