MHT CET · Maths · Permutation Combination
The number of different 9 digit number that can be formed, from the digits of the number 445577888 by rearranging its digits, so that the odd digits occupy even positions, are
- A \(120\)
- B \(60\)
- C \(180\)
- D \(36\)
Answer & Solution
Correct Answer
(B) \(60\)
Step-by-step Solution
Detailed explanation
ways and remaing five even digits \(4,4,8,8,8\) can be arranged in 5 places in \(\frac{\underline{5}}{2 \underline{3}}\)
Hence total no of ways \(=\frac{\lfloor 4}{\lfloor 2 L 2} \times \frac{\underline{5}}{2 \underline{2} \underline{3}}=6 \times 10=60\)
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