MHT CET · Maths · Mathematical Reasoning
The negation of the statement, \(\exists x \in A\) such that \(x+5>8\) is
- A \(\forall x \in A, \quad x+5 \geq 8\)
- B \(\forall x \in A, \quad x+5 \leq 8\)
- C \(\forall x \in A, \quad x+5>8\)
- D \(\exists x \in A\) such that \(x+5 < 8\)
Answer & Solution
Correct Answer
(B) \(\forall x \in A, \quad x+5 \leq 8\)
Step-by-step Solution
Detailed explanation
While doing negation we replace \(\exists\) by \(\forall\) and \(>\) by \(\leq\).
So required statement is \(\forall \mathrm{x} \in \mathrm{A}\) such that \(\mathrm{x}+5 \leq 8\)
So required statement is \(\forall \mathrm{x} \in \mathrm{A}\) such that \(\mathrm{x}+5 \leq 8\)
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