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MHT CET · Maths · Mathematical Reasoning

The negation of the statement "If \(5 < 7\) and \(7>2\), then \(5>2 "\) is

  1. A \(5 < 7\) and \(7>2\) and \(5 \leq 2\)
  2. B \(5 < 7\) and \(7>2\) or \(5 < 2\)
  3. C \(5 < 7\) and \(7>2\) and \(5>2\)
  4. D \(5 < 7\) and \(7>2\) or \(5 \leq 2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(5 < 7\) and \(7>2\) and \(5 \leq 2\)

Step-by-step Solution

Detailed explanation

(D)
Let \(\mathrm{p}: 5 < 7\) and \(\mathrm{q}: 7>2\) and \(\mathrm{r}: 5>2 .\) The logical form of given statement is \((\mathrm{p} \wedge \mathrm{q}) \rightarrow \mathrm{r}\) \(\therefore \quad[(\mathrm{p} \wedge \mathrm{q}) \rightarrow \mathrm{r}] \equiv \sim[\sim(\mathrm{p} \wedge \mathrm{q}) \vee \mathrm{r}]\) \(\quad \equiv(\mathrm{p} \wedge \mathrm{q}) \vee \sim \mathrm{r}\) \([(5 < 7)\) and \((7>2)]\) and \((5 \leq 2)\)