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MHT CET · Maths · Mathematical Reasoning

The negation of \(\mathrm{p} \wedge(\mathrm{q} \rightarrow \mathrm{r})\) is

  1. A \(\sim \mathrm{p} \wedge(\sim \mathrm{q} \rightarrow \sim \mathrm{r})\)
  2. B \(\sim \mathrm{p} \vee(\mathrm{q} \wedge \sim \mathrm{r})\)
  3. C \(\sim \mathrm{p} \vee(\sim \mathrm{q} \rightarrow \sim \mathrm{r})\)
  4. D \(\mathrm{p} \vee(\sim \vee \mathrm{r})\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sim \mathrm{p} \vee(\mathrm{q} \wedge \sim \mathrm{r})\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \sim[\mathrm{p} \wedge(\mathrm{q} \rightarrow \mathrm{r})] \\ & \equiv \sim[\mathrm{p} \wedge(\sim \mathrm{q} \vee \mathrm{r})] \\ & \equiv(\sim \mathrm{p}) \vee \sim(\sim \mathrm{q} \vee \mathrm{r}) \\ & \equiv \sim \mathrm{p} \vee(\mathrm{q} \wedge \sim \mathrm{r})\end{aligned}\)