MHT CET · Maths · Mathematical Reasoning
The negation of \(\mathrm{p} \wedge(\mathrm{q} \rightarrow \mathrm{r})\) is
- A \(\sim \mathrm{p} \wedge(\sim \mathrm{q} \rightarrow \sim \mathrm{r})\)
- B \(\sim \mathrm{p} \vee(\mathrm{q} \wedge \sim \mathrm{r})\)
- C \(\sim \mathrm{p} \vee(\sim \mathrm{q} \rightarrow \sim \mathrm{r})\)
- D \(\mathrm{p} \vee(\sim \vee \mathrm{r})\)
Answer & Solution
Correct Answer
(B) \(\sim \mathrm{p} \vee(\mathrm{q} \wedge \sim \mathrm{r})\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \sim[\mathrm{p} \wedge(\mathrm{q} \rightarrow \mathrm{r})] \\ & \equiv \sim[\mathrm{p} \wedge(\sim \mathrm{q} \vee \mathrm{r})] \\ & \equiv(\sim \mathrm{p}) \vee \sim(\sim \mathrm{q} \vee \mathrm{r}) \\ & \equiv \sim \mathrm{p} \vee(\mathrm{q} \wedge \sim \mathrm{r})\end{aligned}\)
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