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MHT CET · Maths · Mathematical Reasoning

The negation of inverse of \(\sim p \rightarrow q\) is

  1. A \(\sim \mathrm{p} \wedge \mathrm{q}\)
  2. B \(\sim \mathrm{q} \rightarrow \mathrm{p}\)
  3. C \(p \wedge(\sim q)\)
  4. D \(\mathrm{p} \wedge \mathrm{q}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{p} \wedge \mathrm{q}\)

Step-by-step Solution

Detailed explanation

We have \(\sim \mathrm{p} \rightarrow \mathrm{q}\)
Inverse of given statement is
\(
\sim(\sim \mathrm{p}) \rightarrow \sim \text { q i.e. } \mathrm{p} \rightarrow \sim \mathrm{q}
\)
Negation of inverse of given statement is \(\sim(p \rightarrow \sim q)\)
\(
\equiv \sim(\sim p \vee \sim q) \equiv p \wedge q
\)