MHT CET · Maths · Three Dimensional Geometry
The mirror image of the point \(\mathrm{P}(-1,2,-4)\) in the plane \(x-\mathrm{y}-2 \mathrm{z}+1=0\) is
- A \((3,-4,1)\)
- B \((-3,4,0)\)
- C \((4,1,0)\)
- D \((2,-3,0)\)
Answer & Solution
Correct Answer
(B) \((-3,4,0)\)
Step-by-step Solution
Detailed explanation
\( \frac{x' - (-1)}{1} = \frac{y' - 2}{-1} = \frac{z' - (-4)}{-2} = -2 \frac{(1)(-1) + (-1)(2) + (-2)(-4) + 1}{1^2 + (-1)^2 + (-2)^2} \) \( \frac{x' + 1}{1} = \frac{y' - 2}{-1} = \frac{z' + 4}{-2} = -2 \frac{6}{6} = -2 \)
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