MHT CET · Maths · Circle
The minimum distance and maximum distance of the point \(\mathrm{P}(2,-7)\) from the circle \(x^2+y^2-14 x-10 y-151=0\) are respectively _______ units
- A 2,28
- B 5,25
- C 6,24
- D 3,27
Answer & Solution
Correct Answer
(A) 2,28
Step-by-step Solution
Detailed explanation
\(C = \left(\frac{-(-14)}{2}, \frac{-(-10)}{2}\right) = (7,5)\) \(r = \sqrt{7^2 + 5^2 - (-151)} = \sqrt{49 + 25 + 151} = \sqrt{225} = 15\)
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